If (diff component.slice(-2)) // take last 2 digits of every component Let diff = new Date() - date // the difference in milliseconds For instance, browser has performance.now() that gives the number of milliseconds from the start of page loading with microsecond precision (3 digits after the point): JavaScript itself does not have a way to measure time in microseconds (1 millionth of a second), but most environments provide it. Sometimes we need more precise time measurements. Note that unlike many other systems, timestamps in JavaScript are in milliseconds, not in seconds. Use Date.now() to get the current timestamp fast.That’s because a Date becomes the timestamp when converted to a number. Dates can be subtracted, giving their difference in milliseconds.Good for adding/subtracting days/months/hours. Date auto-corrects itself when out-of-range components are set.Days of week in getDay() are also counted from zero (that’s Sunday).Months are counted from zero (yes, January is a zero month).We can’t create “only date” or “only time”: Date objects always carry both. Date and time in JavaScript are represented with the Date object.The call to Date.parse(str) parses the string in the given format and returns the timestamp (number of milliseconds from UTC+0). Shorter variants are also possible, like YYYY-MM-DD or YYYY-MM or even YYYY. The optional 'Z' part denotes the time zone in the format +-hh:mm.HH:mm:ss.sss – is the time: hours, minutes, seconds and milliseconds.The character "T" is used as the delimiter.YYYY-MM-DD – is the date: year-month-day.The string format should be: YYYY-MM-DDTHH:mm:ss.sssZ, where: The method Date.parse(str) can read a date from a string. The great pack of articles about V8 can be found at. And then you probably won’t need microbenchmarks at all. So if you seriously want to understand performance, then please study how the JavaScript engine works. They may tweak results of “artificial tests” compared to “normal usage”, especially when we benchmark something very small, such as how an operator works, or a built-in function. Modern JavaScript engines perform many optimizations. That may lead to wrong results.įor more reliable benchmarking, the whole pack of benchmarks should be rerun multiple times. And by the time of running bench(diffGetTime) that work has finished.Ī pretty real scenario for a modern multi-process OS.Īs a result, the first benchmark will have less CPU resources than the second. Imagine that at the time of running bench(diffSubtract) CPU was doing something in parallel, and it was taking resources. Wow! Using getTime() is so much faster! That’s because there’s no type conversion, it is much easier for engines to optimize. These powerful new features will modernize your JavaScript with shorter and more expressive code.Return date2.getTime() - date1.getTime() įor (let i = 0 i < 100000 i++) f(date1, date2) Īlert( 'Time of diffSubtract: ' + bench(diffSubtract) + 'ms' ) Īlert( 'Time of diffGetTime: ' + bench(diffGetTime) + 'ms' ) This guide will bring you up to speed with all the latest features added in ECMAScript 13. Note that subDays() returns a new Date object without mutating the one passed to it.ġ1 Amazing New JavaScript Features in ES13 It returns a new Date object with the days subtracted. subDays() takes a Date object and the number of days to subtract as arguments. date-fns subDays() functionĪlternatively, we can use the subDays() function from the date-fns NPM package to subtract 30 days from the current date. April 25, 2022Īpril has only 30 days, so passing 40 to setDate() here increments the month by one and sets the day of the month to 10. If the days you specify would change the month or year of the Date, setDate() automatically updates the Date information to reflect this. The Date setDate() method changes the day of the month of the Date object to the number passed as an argument. What I have to fix is: If the result of the date is Monday and Monday - 1 day will yield Sunday, I need to produce Saturday. The Date getDate() method returns a number between 1 and 31 that represents the day of the month of the particular Date. var myDate new Date (date1) //return myDate tDate (myDate.getDate ()-1) //return myDate return FormatDate (myDate,'mm/dd/yyyy') Works fine.
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